In the triangle abc ,D and E are points on sides AB and AC respectivel

1.	In the triangle abc ,D and E are points on sides AB and AC respectively such that de is parallel to bc if AE = 20cm, AD = 3 cm and BD = 4.5 cm, then find CE.
Answer» Answer: AC=8.8 cm Explanation: In ΔABC, D and E are the points on sides AB and AC respectively such that DE parallel to BC as SHOWN in attach figure. AD:DB=3:1 or If EA=6.6 cm Using BASIC PROPORTIONALITY theorem, In a triangle a line is drawn parallel to ONE side of a triangle and intersect the other two side at distinct points, the other two sides are divided in the same ratio. Substitute the value of AD:DB and AE. We get EC=2.2 cm We need to find length of AC. AC=AE+EC AC=6.6+2.2 AC=8.8 cm mark me as the brainiest Step-by-step explanation:

In the triangle abc ,D and E are points on sides AB and AC respectively such that de is parallel to bc if AE = 20cm, AD = 3 cm and BD = 4.5 cm, then find CE.

Answer»

Answer:

AC=8.8 cm

Explanation:

In ΔABC, D and E are the points on sides AB and AC respectively such that DE parallel to BC as SHOWN in attach figure.

AD:DB=3:1 or

If EA=6.6 cm

Using BASIC PROPORTIONALITY theorem, In a triangle a line is drawn parallel to ONE side of a triangle and intersect the other two side at distinct points, the other two sides are divided in the same ratio.

Substitute the value of AD:DB and AE. We get

EC=2.2 cm

We need to find length of AC.

AC=AE+EC

AC=6.6+2.2

AC=8.8 cm

mark me as the brainiest

Step-by-step explanation:

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