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in the square ABCD,AB=24. The diagonals of the square intersect at point P. A circle centered at point P with diameter 26, intersect AB at E and F . Find the length of EF. |
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Answer» ong>Given : in the square ABCD,AB=24. The DIAGONALS of the square intersect at point P. A circle centered at point P with diameter 26, intersect AB at E and F . To FIND : the length of EF. Solution: ABCD is square AB = BC = CD = AD = 24 AC = BD = Diagonal = 24√2 AP = BP = CP = DP = 12√2 Draw a perpendicular PM ⊥ AB PM = 12 PE = PF = 13 ( radius of circle , diameter = 26 => radius = 13) EM² = PE² -PM² = 13² - 12² = 5² => EM = 5 FM² = PF² -PM² = 13² - 12² = 5² => FM = 5 EF = EM + FM = 5 + 5 = 10 the length of EF. = 10 Learn More: 154 ABCD is a square. Two arcs are drawn with A and B as centres ... |
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