Related InterviewSolutions

• If the points `(1,1,p)` and `(-3,0,1)` be equidistant from the plane `vecr.(3hati+4hatj-12hatk)+13`, find the values of p.A. `-1,(-7)/(3)`B. `1,(-7)/(3)`C. `-1,(7)/(3)`D. `1,(7)/(3)`
• Find the equation of a plane containing the line of intersectionof the planes `x+y+z-6=0a n d2x+3y+4z+5=0`passing through `(1,1,1)`.A. `10x+13y+16z+39=0`B. `10x-13y+16z+39=0`C. `10x+13y-16z+39=0`D. `10x+13y-16z-39=0`
• The equation of the plane passing through the points (0,1,2) and (-1,0,3) and perpendicular to the plane `2x+3y+z=5` isA. `3x -4y + 18z+32 =0`B. `3x +4y -18z + 32 =0`C. `4x + 3y -17z + 31 =0`D. `4x -3y + z + 1 =0`
• Find the vector equation of the plane which is at a distance of 5 units from the origin and which is normal to the vector `2hati + hatj + 2hatk`.A. `barr.(2hati+hatj+2hatk)=3`B. `barr.(2hati+hatj+2hatk)=5`C. `barr.(2hati+hatj+2hatk)=15`D. `barr.(2hati+hatj+2hatk)=45`
• The vector equation of the plane passing through the points `(1,-2,1),(2,-1,-3) and (0,1,5)` isA. `barr.(hati-4hatk)=5`B. `barr.(hati+4hatk)=5`C. `barr.(hati-4hatk)=5`D. `barr.(hati+4hatk)=5`
• The equation of plane passing through point (3 ,4 ,5) and parallel to the vectors `hati+2hatj+3hatk and 3hati+2hatj+4hatk` isA. `x+5y-4z+6=0`B. `2x+5y-4z-6=0`C. `2x -5y +z -6 =0`D. `2x+y+4z-7=0`
• The equation of plane in vector form passing through the points `(1 ,0 ,1 ) ,(1 , -1 , 1) and (4 , -3 ,2 )` isA. `barr.(hati-3hatk)=2`B. `barr.(-hati+3hatk)=2`C. `barr.(hati-3hatk)=4`D. `barr.(-hati+3hatk)=4`
• Find the vector equation of the plane passing through the point having position vector `2hati + 3hatj + 4hatk` and perpendicular to the vector `2hati + hatj -2hatk`.A. `barr.(2hati+hatj-2hatk)=-1`B. `barr.(2hati+hatj-2hatk)=8`C. `barr.(2hati+hatj-2hatk)=9`D. `barr.(2hati+hatj-2hatk)=15`
• Find the equation of theplane passing through the line `(x-1)/5=(y+2)/6=(z-3)/4`and point `(4,3,7)dot`A. `4x+8y+7z=41`B. `4x-8y+7z=41`C. `4x-8y-7z=41`D. `4x-8y+7z=39`
• The cartesian equation of the plane passing through the points `(1 ,1,2),(0,2,3) and(4,5,6)` isA. `y-z+1=0`B. `y+z-1=0`C. `y-z-1=0`D. `y+z+1=0`