In the region between the plane `z=0` and `z=a (a gt 0)`, the uniform electric and magnetic fields are given by `vecE=E_(0)(hatk-hatj)`, `vecB=B_(0)hati`. The region defined by `a le z le b` contains only magnetic field `vecB= -B_(0)hati`. Beyond `z gt b` no field exits. A positive point charge `q` is projected from the origin with velocity `v_(0)hatk`. Assuming the mass of the particle to be `(2)/(3)(qE_(0)a)/(v_(0)^(2))`. The value of `E_(0)` such that the particle moves undeviated upto the plane `z=a` is A. `(v_(0)B_(0))/(sqrt(2))`B. `v_(0)B_(0)`C. `v_(0)B_(0)sqrt(2)`D. `(v_(0)B_(0))/(2)`

In the region between the plane `z=0` and `z=a (a gt 0)`, the uniform

1.	In the region between the plane `z=0` and `z=a (a gt 0)`, the uniform electric and magnetic fields are given by `vecE=E_(0)(hatk-hatj)`, `vecB=B_(0)hati`. The region defined by `a le z le b` contains only magnetic field `vecB= -B_(0)hati`. Beyond `z gt b` no field exits. A positive point charge `q` is projected from the origin with velocity `v_(0)hatk`. Assuming the mass of the particle to be `(2)/(3)(qE_(0)a)/(v_(0)^(2))`. The value of `E_(0)` such that the particle moves undeviated upto the plane `z=a` is A. `(v_(0)B_(0))/(sqrt(2))`B. `v_(0)B_(0)`C. `v_(0)B_(0)sqrt(2)`D. `(v_(0)B_(0))/(2)`
Answer» `qv_(0)B=qE_(0)rArrE_(0)=v_(0)B`

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