In the rectangle WXYZ, XY + YZ = 17 cm, and XZ + YW = 26 cm. Calculat

1.	In the rectangle WXYZ, XY + YZ = 17 cm, and XZ + YW = 26 cm. Calculate the length and breadth of the rectangle?
Answer» XY + YZ = 17 cm … (1) XZ + YW = 26 cm … (2) (2) ⇒ XZ = 13, YW = 13 (∵ In rectangle diagonals are equal). (1) ⇒ XY = 5, YZ = 12 XY + YZ = 17 ⇒ Using Pythagoras theorem 5² + 12² = 25 + 144 = 169 = 13² ∴ In ΔXYZ = 13² = 5² + 12² it is verified ∴ The length is 12 cm and the breadth is 5 cm.

In the rectangle WXYZ, XY + YZ = 17 cm, and XZ + YW = 26 cm. Calculate the length and breadth of the rectangle?

Answer»

XY + YZ = 17 cm … (1)

XZ + YW = 26 cm … (2)

(2) ⇒ XZ = 13, YW = 13

(∵ In rectangle diagonals are equal).

(1) ⇒ XY = 5, YZ = 12 XY + YZ = 17

⇒ Using Pythagoras theorem

5² + 12² = 25 + 144 = 169 = 13²

∴ In ΔXYZ = 13² = 5² + 12² it is verified

∴ The length is 12 cm and the breadth is 5 cm.