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In the reaction H-C≡ CH\xrightarrow[{CH3CH2Br}]{NaNH2/liq. NH3}X\xrightarrow[{CH3CH2Br}]{NaNH2/liq.NH3}Y X and Y ar

Answer» In the reaction H-C≡ CH\xrightarrow[{CH3CH2Br}]{NaNH2/liq. NH3}X\xrightarrow[{CH3CH2Br}]{NaNH2/liq.NH3}Y X and Y ar


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