1.

In the question number 62, the linear acceleration of the rope is

Answer»

`5 m s^(-2)`
`10 m s^(-2)`
`15 m s^(-2)`
`20 m s^(-2)`

Solution :From the above solution, `alpha=25 rad s^(-2)`
Linear acceleration, `a=alphaR=(25 rad s^(-2))(40 xx 10^(-2))=10ms^(-2)`


Discussion

No Comment Found