In the question number 51 , the potential at the centre is

1.	In the question number 51 , the potential at the centre is
Answer» `-2(GM)/(l)` `3sqrt(2)(Gm)/(l)` `-2sqrt(2)(Gm)/(l)` `-4sqrt(2)(Gm)/(l)` Solution :(d) From FIGURE `OA=OB=OC=OD` `=(SQRT(l^(2)+l^(2)))/(2)=(lsqrt(2))/(2)=(l)/(2)` Potential at centre O due to given mass configuration is `V=(-(Gm)/(OA))+(-(Gm)/(OB))+(-(Gm)/(OC))+(-(Gm)/(OD))` ` = -(4GM)/(lsqrt(2))=-4sqrt(2)(Gm)/(l)`

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