In the question number 38, the speed of the particle at this time is

1.	In the question number 38, the speed of the particle at this time is
Answer» 16 m `s^(-1)` 26 m `s^(-1)` 36 m `s^(-1)` 46 m `s^(-1)` SOLUTION :Using eqn. (i) from question number 38, Velocity, `VECV = (dvecr)/(dt) = (d)/(dt) (5T +1.5t^(2)) hati + 1t^(2)hatj = (5+3t)hati +2thatj` At` = 6s, vecv = 23 hati + 12 hatj` The speed of the particle is `\|vecv\| = SQRT((23)^(2) + (12)^(2)) = 26` m `s^(-1)`

Discussion