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In the parallelogram PQRS, P(-3, 2) Q(2, 7), S(1, 9) are three vertices. Find the length of the diagonal PR. |
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Answer» x coordinate of R = 2 + 1 – (–3) = 6 y coordinate of R = 9 + 7 – 2 = 14 (6, 14) is the coordinate of R \(PR=\sqrt{((6-(-3))^2+((14-2))^2}\) = \(\sqrt{9^2+12^2}\) = 15 unit |
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