1.

In the interval `2/pi

Answer» `A = [[2sinx,3],[1,2sinx]]`

Matrix `A` will be singular if `|A| = 0`
Here, `|A| = 2sinx(2sinx) -3(1) = 4sin^2x -3`
`:. 4sin^2x-3 = 0 =>sin^2x = 3/4`
`=>sinx = +-sqrt3/2 `
As, `x in (pi/2,pi)`,
`:. x = (pi-pi/3) = (2pi)/3`


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