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In the interval `2/pi |
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Answer» `A = [[2sinx,3],[1,2sinx]]` Matrix `A` will be singular if `|A| = 0` Here, `|A| = 2sinx(2sinx) -3(1) = 4sin^2x -3` `:. 4sin^2x-3 = 0 =>sin^2x = 3/4` `=>sinx = +-sqrt3/2 ` As, `x in (pi/2,pi)`, `:. x = (pi-pi/3) = (2pi)/3` |
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