1.

In the given triangle PQR, ∠QPR= 90º, PQ= 24cm and QR = 26 cm and in triangle PKR ,∠PKR =90º and KR = 8 cm, the length of PK will be

Answer»

In ΔPQR, PQ = 24 cm

QR = 26 cm

∠QPR = 90°

By using pythagoras theorem,

⇒ QR2 = QP2+PR2

⇒ 262 = 242+PR2

⇒ 676 = 576+PR2

⇒ PR2 = 100

⇒ PR = 10 cm  ...(1)

In ΔPKR, KR = 8 cm

∠PKR = 90°

By using pythagoras theorem,

⇒ PR2 = PK2+KR2

⇒ 102 = PK2+82

⇒ 100 = PK2+64

⇒ PK2 = 36

⇒ PK = 6 cm



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