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In the given triangle PQR, ∠QPR= 90º, PQ= 24cm and QR = 26 cm and in triangle PKR ,∠PKR =90º and KR = 8 cm, the length of PK will be |
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Answer» In ΔPQR, PQ = 24 cm QR = 26 cm ∠QPR = 90° By using pythagoras theorem, ⇒ QR2 = QP2+PR2 ⇒ 262 = 242+PR2 ⇒ 676 = 576+PR2 ⇒ PR2 = 100 ⇒ PR = 10 cm ...(1) In ΔPKR, KR = 8 cm ∠PKR = 90° By using pythagoras theorem, ⇒ PR2 = PK2+KR2 ⇒ 102 = PK2+82 ⇒ 100 = PK2+64 ⇒ PK2 = 36 ⇒ PK = 6 cm |
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