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In the given network, calculate the potential difference between the points B and D |
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Answer» SOLUTION :a, B are in SERIES. `therefore R_(1)=2+3=5Omega` c, d are in series `therefore R_(2)=20+5=25Omega` `I_(1)=I[(R )/(R_(1)+R_(2))]=4[(25)/(30)]=(10)/(3)A` `I_(2)=I[(R_(1))/(R_(1)+R_(2))]=4[(5)/(30)]=(2)/(3)A` `V_(A)-V_(B)=I_(1)[R_(a)]=(10)/(3)[2]=(20)/(3)" volt"` `V_(A)-V_(D)=I_(2)[R_(d)]=(2)/(3)[5]=(10)/(3)" volt"` `therefore R_(B)-V_(D)=(10)/(3)-(20)/(3)=-(10)/(3)" volts"` |
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