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In the given figure, XOy is a straight line and OQLXY at O. Show thatta |
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Answer» OP perpendicular XYSo, /_XOQ= /_QOY(each 90 degree)------------> (i)/_QOP=/_XOQ- /_XOP--------------> (ii)/_QOP = /_POY- /_QOY --------------> (iii)But, /_QOP= /_ QOY- /_XOP[from (i)] adding (ii) and (iii)2/_QOP=/_QOY - /_XOP+ /_POY-/_QOY=> 2/_QOP= /_POY - /_XOP |
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