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In the given figure, there are two circles with centers A and B. The common tangent to the circles touches them, respectively,at P and Q. AR is 40cm and AB is divided by the point of contact of the circles in the ratio `5:3` The radius of the circle with center B isA. 10 cmB. 3 cmC. 6cmD. 8cm |
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Answer» Correct Answer - 3 `(r_(1))/(r_(2))=(5)/(3)` `:. (r_(1)+r_(2))/(r_(2))=(8)/(3)` `:. r_(2)=((40-24)3)/(8)=6 cm` |
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