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In the given figure, there are two circles with centers A and B. The common tangent to the circles touches them, respectively,at P and Q. AR is 40cm and AB is divided by the point of contact of the circles in the ratio `5:3` The length of QR isA. `10sqrt(15)` cmB. `5 sqrt(15) cm`C. `4 sqrt(15)` cmD. `6 sqrt(15)` cm |
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Answer» Correct Answer - 4 `QR =sqrt((BR)^(2)-r_(2)^(2))=sqrt((24)^(2)-36)=6 sqrt(15) cm` |
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