In the given figure, the radius of the circle AB = AC = 5 cm and BC is

1.	In the given figure, the radius of the circle AB = AC = 5 cm and BC is a chord. Findits distance from the centre, if Angle ABC = 60.
Answer» ANSWER: $\frac{5\sqrt{3} }{2}$ Step-by-step explanation: AB+AC=5cm[radius] Angle ABC= Angle ACB[angle opposite to equal side] It distance = height od the TRIANGLE you can use sin∅ or cos∅ The height/Side=sin60° h/5=√3/2 H= $\frac{5\sqrt{3} }{2}$ Hope you will LIKE the answer. [Answered by expert] I had done my best effort to give you correct answer. If you are satisfied with the answer then you can MARK me brainliest.

In the given figure, the radius of the circle AB = AC = 5 cm and BC is a chord. Findits distance from the centre, if Angle ABC = 60.

Answer»

ANSWER:

$\frac{5\sqrt{3} }{2}$

Step-by-step explanation:

AB+AC=5cm[radius]

Angle ABC= Angle ACB[angle opposite to equal side]

It distance = height od the TRIANGLE

you can use sin∅ or cos∅

The height/Side=sin60°

h/5=√3/2

H= $\frac{5\sqrt{3} }{2}$

Hope you will LIKE the answer.

[Answered by expert]

I had done my best effort to give you correct answer.

If you are satisfied with the answer then you can MARK me brainliest.

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In the given figure, the radius of the circle AB = AC = 5 cm and BC is a chord. Findits distance from the centre, if Angle ABC = 60.​

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In the given figure, the radius of the circle AB = AC = 5 cm and BC is a chord. Findits distance from the centre, if Angle ABC = 60.