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In the given figure, the point Pbisects AB and DC. Provethat ∆APC~∆BPD |
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Answer» in the figure <APC is equal to <BPDP bisect AB so AP=BP....similarly CP=DP......in triangle APC and triangle BPD ..AP=BP (given). CD=DP(given ).and angle BPD =angle APC (vertically opposite angle) .so by SAS criteria triangles are congruent |
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