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In the given figure sides QP and RQ of ∠PQR are produced to points S and T respectively. If ∠SPR = 135° and ∠PQT = 110°, find ∠PRQ. |
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Answer» Given that ∠SPR = 135° and ∠PQT =110° From the figure ∠SPR + ∠RPQ = 180° ∠PQT + ∠PQR = 180° [∵ linear pair of angles] ⇒ ∠RPQ = 180° – ∠SPR = 180° – 135° = 45° ⇒ ∠PQR = 180° – ∠PQT = 180°-110° = 70° Now in APQR ∠RPQ + ∠PQR + ∠PRQ = 180° [∵ angle sum property] ∴ 45° + ’70° + ∠PRQ = 180° ∴ ∠PRQ = 180°-115° = 65° |
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