In the given figure, seg AD ⊥ seg BC. seg AE is the bisector of ∠CAB and C - E - D. Prove that∠DAE = 12∠C - ∠B

In the given figure, seg AD ⊥ seg BC. seg AE is the bisector of ∠

1.	In the given figure, seg AD ⊥ seg BC. seg AE is the bisector of ∠CAB and C - E - D. Prove that∠DAE = 12∠C - ∠B
Answer» In the given figure, seg AD $⊥$ seg BC. seg AE is the bisector of $∠$ CAB and C - E - D. Prove that $∠$ DAE = $\frac{1}{2} (∠ C - ∠ B)$