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In the given figure, PT touches the circle whose center is O, at R. Diameter SQ when produced meets PT at P. If ∠SPR = x°, ∠QRP = y°, then x + 2y =(a) 100° (b) 120° (c) 80° (d) 90° |
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Answer» Answer : (d) 90º ∠QSR = ∠QRP = y° (Angles in alternate segment are equal) Also, ∠QRS = 90° (Angle in a semi-circle) ∠PRS = ∠PRQ + ∠QRS = y° + 90° In ∆ PRS, ∠SPR + ∠PRS + ∠PSR = 180° ⇒ x° + y° + 90° + y° = 180° ⇒ x + 2y = 90°. |
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