In the given figure, PQ and PR are tangents to the circle with centre

1.	In the given figure, PQ and PR are tangents to the circle with centre O such that ∠QPR = 50°, then find ∠OQR.
Answer» ∠QPR = ∠50° (Given) ∴ ∠QOR = 180° – 50° = 130° ΔOQR is an isosceles triangle. From ΔOQR ∠OQR = ∠ORQ = (180 - 130)/2 = 50/ 2 = 25°

In the given figure, PQ and PR are tangents to the circle with centre O such that ∠QPR = 50°, then find ∠OQR.

Answer»

∠QPR = ∠50° (Given)

∴ ∠QOR = 180° – 50° = 130°

ΔOQR is an isosceles triangle.

From ΔOQR

∠OQR = ∠ORQ = (180 - 130)/2

= 50/ 2

= 25°

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In the given figure, PQ and PR are tangents to the circle with centre O such that ∠QPR = 50°, then find ∠OQR.

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