In the given figure, P is a point in the interior of a parallelogram A

1.	In the given figure, P is a point in the interior of a parallelogram ABCD. Show that(i) ar (APB) + ar (PCD) = ar (ABCD)(ii) ar (APD) + ar (PBC) = ar (APB) + ar (PCD)[Hint: Through. P, draw a line parallel to AB]
Answer» In the given figure, P is a point in the interior of a parallelogram ABCD. Show that (i) ar (APB) + ar (PCD) = ar (ABCD) (ii) ar (APD) + ar (PBC) = ar (APB) + ar (PCD) [Hint: Through. P, draw a line parallel to AB]

In the given figure, P is a point in the interior of a parallelogram ABCD. Show that(i) ar (APB) + ar (PCD) = ar (ABCD)(ii) ar (APD) + ar (PBC) = ar (APB) + ar (PCD)[Hint: Through. P, draw a line parallel to AB]

Answer»

In the given figure, P is a point in the interior of a parallelogram ABCD. Show that

(i) ar (APB) + ar (PCD) = ar (ABCD)

(ii) ar (APD) + ar (PBC) = ar (APB) + ar (PCD)

[Hint: Through. P, draw a line parallel to AB]