In the given figure \(\overrightarrow{CF}|| \overrightarrow{BD}, \over

1.	In the given figure \(\overrightarrow{CF}\|\| \overrightarrow{BD}, \overrightarrow{BE}\) is transversal. ∠CAE = 135°, then find ∠ABD
Answer» Given \(\overrightarrow{CF}\|\| \overrightarrow{BD}, \overrightarrow{BE}\) is transversal. ∠CAE = 135° ∠BAF = ∠CAE = 135° (vertically opposite angles) ∴ ∠BAF = 135° ∠BAF + ∠ABD = 180° (co-interior angles are supplementary)

In the given figure \(\overrightarrow{CF}|| \overrightarrow{BD}, \overrightarrow{BE}\) is transversal. ∠CAE = 135°, then find ∠ABD

Answer»

Given \(\overrightarrow{CF}|| \overrightarrow{BD}, \overrightarrow{BE}\) is transversal.

∠CAE = 135°

∠BAF = ∠CAE = 135° (vertically opposite angles)

∴ ∠BAF = 135° ∠BAF + ∠ABD = 180°

(co-interior angles are supplementary)