In the given figure, O is the centre of the circle, AB and CD are the

1.	In the given figure, O is the centre of the circle, AB and CD are the chords of the circle which intersect at P. If PA=4 cm, PB = 6 cm, OB 7 cm and CD is 1 cm greater than twice of OP, then the difference between the length of PD and PC is
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In the given figure, O is the centre of the circle, AB and CD are the chords of the circle which intersect at P. If PA=4 cm, PB = 6 cm, OB 7 cm and CD is 1 cm greater than twice of OP, then the difference between the length of PD and PC is

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SORRY I didn't UNDERSTAND

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In the given figure, O is the centre of the circle, AB and CD are the chords of the circle which intersect at P. If PA=4 cm, PB = 6 cm, OB 7 cm and CD is 1 cm greater than twice of OP, then the difference between the length of PD and PC is​

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In the given figure, O is the centre of the circle, AB and CD are the chords of the circle which intersect at P. If PA=4 cm, PB = 6 cm, OB 7 cm and CD is 1 cm greater than twice of OP, then the difference between the length of PD and PC is