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In the given figure ( no to scale), ABCD is a cyclic quadrilateral, `bar(DE)_|_bar(AB), /_BAO=40^(@)=40^(@),/_OAD=20^(@)` and `/_OCD=50^(@)/_ABC=` |
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Answer» (a) Opposite angles of a cyclic quadrilateral are supplementary. Sume of the angles of a triangle is `180^(@)`. (b) In the cyclic quadrilateral ABCD , `/_BAD+/_BCD=180^(@)`. (c ) Find the angle ACB using the given angles. (d ) Use the property that sum of angles of a triangle is `180^(@)` is find `/_ABC`. |
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