In the given figure, line l is the bisector of an angle ∠A and B is

1.	In the given figure, line l is the bisector of an angle ∠A and B is any point on l.If BP and BQ are perpendiculars from B to the arms of ∠A, show that(i) ΔAPB≅ ΔAQB(ii) BP = BQ, i.e., B is equidistant from the armos of ∠A.
Answer» $In the given figure, line l is the bisector of an angle ∠ A and B is any point on l. If BP and BQ are perpendiculars from B to the arms of ∠ A, show that (i) Δ A P B ≅ Δ A Q B (ii) BP = BQ, i.e., B is equidistant from the armos of ∠ A .$

In the given figure, line l is the bisector of an angle ∠A and B is any point on l.If BP and BQ are perpendiculars from B to the arms of ∠A, show that(i) ΔAPB≅ ΔAQB(ii) BP = BQ, i.e., B is equidistant from the armos of ∠A.

Answer»

$In the given figure, line l is the bisector of an angle ∠ A and B is any point on l. If BP and BQ are perpendiculars from B to the arms of ∠ A, show that (i) Δ A P B ≅ Δ A Q B (ii) BP = BQ, i.e., B is equidistant from the armos of ∠ A .$

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In the given figure, line l is the bisector of an angle ∠A and B is any point on l.If BP and BQ are perpendiculars from B to the arms of ∠A, show that(i) ΔAPB≅ ΔAQB(ii) BP = BQ, i.e., B is equidistant from the armos of ∠A.

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