In the given figure, it is given that, BC // DE, ∠BAC = 35° and ∠

1.	In the given figure, it is given that, BC // DE, ∠BAC = 35° and ∠BCE = 102°. Find the measure of 0 ∠ADE
Answer» Given that BC // DE ; ∠BAC = 35°; ∠BCE = 102° ∠ADE + ∠CBD = 180° (∵ interior angles on the same side of the transversal) ∠ADE + (78° + 35°) = 180° (∵ ∠CBD = ∠BAC + ∠BCA) ∴ ∠ADE = 180° – 113° = 67°

In the given figure, it is given that, BC // DE, ∠BAC = 35° and ∠BCE = 102°. Find the measure of 0 ∠ADE

Answer»

Given that BC // DE ; ∠BAC = 35°; ∠BCE = 102°

∠ADE + ∠CBD = 180°

(∵ interior angles on the same side of the transversal)

∠ADE + (78° + 35°) = 180°

(∵ ∠CBD = ∠BAC + ∠BCA)

∴ ∠ADE = 180° – 113° = 67°