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In the given figure, it is given that, BC // DE, ∠BAC = 35° and ∠BCE = 102°. Find the measure of 0 ∠BCA |
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Answer» Given that BC // DE ; ∠BAC = 35°; ∠BCE = 102° From the figure 102° + ∠BCA = 180° (∵ linear pair of angles) ∴ ∠BCA = 180° – 102° = 78° |
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