1.

In the given figure, it is given that, BC // DE, ∠BAC = 35° and ∠BCE = 102°. Find the measure of 0 ∠BCA 

Answer»

Given that BC // DE ; ∠BAC = 35°; 

∠BCE = 102° 

From the figure 

102° + ∠BCA = 180° 

(∵ linear pair of angles) 

∴ ∠BCA = 180° – 102° = 78°



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