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In the given figure if PQ ⊥ PS; PQ // SR, ∠SQR = 28° and ∠QRT = 65°, then find the values of x and y. |
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Answer» Given that PQ ⊥ PS ; PQ // SR ∠SQR = 28°, ∠QRT = 65° From the figure ∠QSR = x° (∵ alt. int. angles for the lines PQ // SR) Also 65° = x + 28° (∵ ext. angles = sum of the opp. interior angles) ∴ x° = 65° – 28° = 37° And x° + y° = 90° [ ∵ PQ ⊥ PS and PQ // SR. ⇒ ∠P = ∠S] 37° + y = 90° ∴ y = 90° – 37° = 53° |
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