1.

In the given figure if PQ ⊥ PS; PQ // SR, ∠SQR = 28° and ∠QRT = 65°, then find the values of x and y.

Answer»

Given that PQ ⊥ PS ; PQ // SR 

∠SQR = 28°, ∠QRT = 65° 

From the figure 

∠QSR = x° (∵ alt. int. angles for the lines PQ // SR) 

Also 65° = x + 28° 

(∵ ext. angles = sum of the opp. interior angles) 

∴ x° = 65° – 28° = 37° 

And x° + y° = 90° 

[ ∵ PQ ⊥ PS and PQ // SR. ⇒ ∠P = ∠S] 

37° + y = 90° 

∴ y = 90° – 37° = 53°



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