In the given figure, if AB || DE, ∠BAC = 35º and ∠CDE = 53º, f – InterviewSolution

1.

In the given figure, if AB || DE, ∠BAC = 35º and ∠CDE = 53º, find ∠DCE.

Answer»

AB || DE and AE is a transversal

∠BAC = ∠CED (Alternate interior angles)

∠CED = 35º

In ΔCDE,

∠CDE + ∠CED + ∠DCE = 180º (Angle sum property of a triangle)

53º + 35º + ∠DCE = 180º

∠DCE = 180º − 88º

∠DCE = 92º

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