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In the given figure if ∠A = ∠C then prove that ∆AOB ~ ∆COD. |
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Answer» In triangles ∆AOB and ∆COD ∠A = ∠C (Y given) ∠AOB = ∠COD [∵ Vertically opposite angles] ∠ABO = ∠CDO [Remaining angles of ∆AOB and ∆COD] ∴ ∆AOB ~ ∆COD [∵ AAA similarity] ∵ ∆AOB ~ ∆COD [∵ AAA similarity] |
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