1.

In the given figure if ∠A = ∠C then prove that ∆AOB ~ ∆COD.

Answer»

In triangles ∆AOB and ∆COD

∠A = ∠C (Y given)

∠AOB = ∠COD [∵ Vertically opposite angles]

∠ABO = ∠CDO [Remaining angles of ∆AOB and ∆COD]

∴ ∆AOB ~ ∆COD [∵ AAA similarity]

∵ ∆AOB ~ ∆COD [∵ AAA similarity]



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