In the given figure, E is the midpoint of side AC and D is the midpoin

1.	In the given figure, E is the midpoint of side AC and D is the midpoint of side AB, then S1: DE = 12BC and DE \|\| BC S2: Midpoint Theorem: A line segment joining midpoints of 2 sides of a triangle is parallel to the third side and is half of it.
Answer» In the given figure, E is the midpoint of side AC and D is the midpoint of side AB, then S1: DE = $\frac{1}{2}$ BC and DE \|\| BC S2: Midpoint Theorem: A line segment joining midpoints of 2 sides of a triangle is parallel to the third side and is half of it.

In the given figure, E is the midpoint of side AC and D is the midpoint of side AB, then S1: DE = 12BC and DE || BC S2: Midpoint Theorem: A line segment joining midpoints of 2 sides of a triangle is parallel to the third side and is half of it.

Answer»

In the given figure, E is the midpoint of side AC and D is the midpoint of side AB, then

S1: DE = $\frac{1}{2}$ BC and DE || BC

S2: Midpoint Theorem: A line segment joining midpoints of 2 sides of a triangle is parallel to the third side and is half of it.