1.

In the given figure ΔABC side AC has been produced to D. ∠BCD = 125° and ∠A: ∠B = 2:3, find the measure of ∠A and ∠B

Answer»

Given that ∠BCD = 125° 

∠A : ∠B = 2 : 3 

Sum of the terms of the ratio

∠A : ∠B = 2 + 3 = 5 

We know that ∠A + ∠B = ∠BCD 

(∵ exterior angles of triangle is equal to sum of its opp. interior angles)

∴ ∠A = 2/5 x 125° = 50°

∠B = 3/5 x 125° = 75°



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