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In the given figure ΔABC side AC has been produced to D. ∠BCD = 125° and ∠A: ∠B = 2:3, find the measure of ∠A and ∠B |
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Answer» Given that ∠BCD = 125° ∠A : ∠B = 2 : 3 Sum of the terms of the ratio ∠A : ∠B = 2 + 3 = 5 We know that ∠A + ∠B = ∠BCD (∵ exterior angles of triangle is equal to sum of its opp. interior angles) ∴ ∠A = 2/5 x 125° = 50° ∠B = 3/5 x 125° = 75° |
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