In the given figure BC is a diameter of the circle and angle BAO =60 �

1.	In the given figure BC is a diameter of the circle and angle BAO =60 ° . Then angle ADC is equals to ?please mention the steps also
Answer» Answer: In ΔAOB, ∠OBA = ∠BAO [angles OPPOSITE to equal SIDES are equal] ∠OBA = 60° [∴ ∠BAO = 60°, GIVEN] ∠ABC=∠ADC [angles in the same segment AC are equal] ∠ADC = 60° hope it helps tq./ Step-by-step EXPLANATION:

In the given figure BC is a diameter of the circle and angle BAO =60 ° . Then angle ADC is equals to ?please mention the steps also

Answer»

Answer:

In ΔAOB,

∠OBA = ∠BAO

[angles OPPOSITE to equal SIDES are equal]

∠OBA = 60° [∴ ∠BAO = 60°, GIVEN]

∠ABC=∠ADC

[angles in the same segment AC are equal]

∠ADC = 60°

hope it helps

tq./

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In the given figure BC is a diameter of the circle and angle BAO =60 ° . Then angle ADC is equals to ?please mention the steps also ​

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In the given figure BC is a diameter of the circle and angle BAO =60 ° . Then angle ADC is equals to ?please mention the steps also