1.

In the given figure,angleCAB =40°, AC=AB and BC =BD. Find:¡] angleACB ¡¡]angleCDB ​

Answer»

Answer:

AC = AB

SO angleACB and angle CBA are equal

let them to be x

angle CAB+ACB+CBA=180( ANGLE SUM PROPERTY)

40 +X+X=180

40+2X=180

2X=180-40

×=140/2

X=70

i.e ACB=70

CBA + CBD=180(linear PAIR)

70+y = 180

y=110

CDB= 110

BC=BD

so angle BCD AND BDC are equal

let them be k

CDB+BCD+BDC=180

110 +K+K=180

2K=70

K=35

THIS MEANS BCD = 35


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