1.

in the given figure, AD 13 cm, BC 12 cm,AB 3 cm and angle ACD angle ABC 90Find the length of DC.

Answer»

from triangle ABC we can find ACAC^2 =AB^2 +BC^2 AC^2=3^2 +12^2AC^2 =9+144AC^2=153now in triangle ADCAC^2 +DC^2 =AD^2153+DC^2 =13^2DC^2=169-153DC^2 =16DC=4cm



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