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In the given figure, ABCD is a rhombus and E is a point that lies on DC. The value of (∠AEC+∠EAC–∠CBD) is equal to |
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Answer» In the given figure, ABCD is a rhombus and E is a point that lies on DC. The value of (∠AEC+∠EAC–∠CBD) is equal to |
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