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In the given figure, ABCD is a quadrilateral shaped field in which diagonal BD is 36m, AL ⊥ BD and CM ⊥ BD such that AL=19m and CM=11m. Find the area of the field. |
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Answer» The given details are, AL ⊥ BD and CM ⊥ BD AL=19m, CM=11m, BD=36m By using the formula, Area (quad.ABCD) = area (△ABD) + area(△ACD) Area of triangle=1/2 × base × height ∴ Area (quad.ABCD) = (½ × BD × AL) + (½ × BD × CM) = (½ × 36 × 19) + (½ × 36 × 11) = 342 + 198 = 540m2 |
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