In the given figure, ABC is aright-angled triangle with B= 90°)AB = 4

1.	In the given figure, ABC is aright-angled triangle with B= 90°)AB = 48 cm and BC = 14 cm. With AC asdiameter a semicircle is drawn and withBC as radius, a quadrant of a circle isdrawn. Find the area of the shaded region.
Answer» Answer: In triangle ABC , right angled at B, AC^2=AB^2+BC^2 (phythagoras therom) 28^2+21^2 784+441 = 1225 AC=35cm Area of shaded REGION = Area of TRIANGLEABC + Area of SEMI circle with diameter AC - area of quadrant with radius BC 1/2(2128)+1/222/735/235/2 -1/422/721*21 =294+481.25-346.5 775.25-346.5 =428.75 cm ^2

In the given figure, ABC is aright-angled triangle with B= 90°)AB = 48 cm and BC = 14 cm. With AC asdiameter a semicircle is drawn and withBC as radius, a quadrant of a circle isdrawn. Find the area of the shaded region.

Answer»

Answer:

In triangle ABC , right angled at B,

AC^2=AB^2+BC^2

(phythagoras therom)

28^2+21^2

784+441 = 1225

AC=35cm

Area of shaded REGION = Area of TRIANGLEABC + Area of SEMI circle with diameter AC - area of quadrant with radius BC

1/2(21*28)+1/2*22/7*35/2*35/2

-1/4*22/7*21*21
=294+481.25-346.5
775.25-346.5
=428.75 cm ^2

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In the given figure, ABC is aright-angled triangle with B= 90°)AB = 48 cm and BC = 14 cm. With AC asdiameter a semicircle is drawn and withBC as radius, a quadrant of a circle isdrawn. Find the area of the shaded region.​

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In the given figure, ABC is aright-angled triangle with B= 90°)AB = 48 cm and BC = 14 cm. With AC asdiameter a semicircle is drawn and withBC as radius, a quadrant of a circle isdrawn. Find the area of the shaded region.