In the given figure, ABC is a triangle and FD is a median of ΔFBC. If DE||BF,AB||DF and area of ΔABC=48 cm2, then ar(ΔADF)+ar(ΔBDE) is

In the given figure, ABC is a triangle and FD is a median of ΔFBC. If

1.	In the given figure, ABC is a triangle and FD is a median of ΔFBC. If DE\|\|BF,AB\|\|DF and area of ΔABC=48 cm2, then ar(ΔADF)+ar(ΔBDE) is
Answer» In the given figure, ABC is a triangle and FD is a median of $Δ F B C . I f D E \| \| B F, A B \| \| D F a n d a r e a o f Δ A B C = 48 c m^{2}, t h e n a r (Δ A D F) + a r (Δ B D E) i s$