In the given figure AB||PQ||CD, AB = x units, CD= y units and PQ = z u

1.	In the given figure AB\|\|PQ\|\|CD, AB = x units, CD= y units and PQ = z units, then 1x+1y=
Answer» In the given figure AB\|\|PQ\|\|CD, AB = x units, CD= y units and PQ = z units, then $\frac{1}{x} + \frac{1}{y} =$

In the given figure AB||PQ||CD, AB = x units, CD= y units and PQ = z units, then 1x+1y=

Answer»

In the given figure AB||PQ||CD, AB = x units, CD= y units and PQ = z units, then $\frac{1}{x} + \frac{1}{y} =$