In the given figure ,AB parallel to CD . Prove that angle BAE- angle E

1.	In the given figure ,AB parallel to CD . Prove that angle BAE- angle ECD = AEC
Answer» ANSWER: PRODUCE a BA to touch EC. LET the point of INTERSECTION be F. Then, ∠AFE=∠ECD Also, ∠BAE=∠AFE+∠AEC Therefore, ∠BAE=∠ECD+∠AEC ∠BAE−∠ECD=∠AEC

In the given figure ,AB parallel to CD . Prove that angle BAE- angle ECD = AEC

Answer»

ANSWER:

PRODUCE a BA to touch EC. LET the point of INTERSECTION be F.

Then,

∠AFE=∠ECD

Also, ∠BAE=∠AFE+∠AEC

Therefore,

∠BAE=∠ECD+∠AEC

∠BAE−∠ECD=∠AEC

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In the given figure ,AB parallel to CD . Prove that angle BAE- angle ECD = AEC​

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In the given figure ,AB parallel to CD . Prove that angle BAE- angle ECD = AEC