Saved Bookmarks
| 1. |
In the given figure, AB is a diameter of the circle wuth centre O. DO is parallel to CB and angle DCB = 120°. Calculate :i) angle DAB ii) angle DBA iii) angle DBCiv) angle ADCAlso prove that triangle AOD ia an equilateral triangle. |
|
Answer» Answer: i)angle DAB=60degree ii)angleDBA=30degree ii)angleDBC=30degree iii)angleADC=120degree angle AOD =180-angleDOB 180-120=60degree---(i) angleODA=angleADB-angleBDO 90degree-30degree 60degree-------(ii) angleDAO==angleODA-----(opp. angle of opposite sides) -------(iii) from(i),(ii),(iii)TRIANGLE AOD IS EQUILATERAL TRIANGLE HOPE YOU SATISFIED MARK AS BRAINLIST FOLLOW FOR MORE SOLUTIONS
|
|