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In the given figure, AB || DC and BCE is a straight line.If ∠ABC = 50° and ∠BAC : ∠ACB = 2:3, find ∠ACD.Plz solve these answer.... |
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Answer» Answer: As AB || DE, AE is CROSSING both the PARALLEL lines. So, ∠BAE=∠AED=40 o
In △CDE ∠AED+∠EDC+∠DCE=180 43+40+∠DCE=180 ∠DCE=97 As ace is straight line So, ∠DCE+∠ACD=180 ∠ACD=180−97=83 Answer (C) 83 Step-by-step explanation:
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