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In the given figure, AB || CD, ∠ABE = 120°, ∠ECD = 100° and ∠BEC = x°. Find the value of x |
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Answer» ★In the given FIGURE, AB || CD, ∠ABE = 120°, ∠ECD = 100° and ∠BEC = x°. FIND the value of x ★In the given figure, AB || CD, ∠ABE = 120°, ∠ECD = 100° ★The value of x ★Through E, draw FEG || AB || CD. Now, FE || AB And BE is the transversal. ∴ ∠BEF + ∠ABE = 180° ==> ∠BEF + 120° = 180° [co-interior ANGLE] ==> ∠BEF = (180° – 120°) ==> ∠BEF = 60° Again, CD || EG and CE is the transversal. ∴ ∠CEG + ∠ECD = 180° [co-interior angle] ==> ∠CEG + 100° = 180° ==> ∠CEG = (180° – 100°) ==> ∠CEG = 80° Now, FEG is a straight line. ∴ ∠BEF + ∠BEC + ∠CEG = 180° ==> 60° + x° + 80° = 180° ==> x + 140° = 180° ==> x = (180° – 140°) ==> x = 40° Hence, the value of x is 40° ━─━─━─━─━──━─━─━─━─━─━─━━─━─━─━ |
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