1.

In the given figure, AB || CD, ∠ABE = 120°, ∠ECD = 100° and ∠BEC = x°. Find the value of x​

Answer»

\bf\underline{\underline{\pink{Question:-}}}

★In the given FIGURE, AB || CD, ∠ABE = 120°, ∠ECD = 100° and ∠BEC = x°. FIND the value of x

\bf\underline{\underline{\blue{Given:-}}}

★In the given figure, AB || CD, ∠ABE = 120°, ∠ECD = 100°

\bf\underline{\underline{\green{ToFind:-}}}

★The value of x

\bf\underline{\underline{\red{Construction:-}}}

★Through E, draw FEG || AB || CD.

\bf\underline{\underline{\orange{Solution:-}}}

Now, FE || AB And BE is the transversal.

∴ ∠BEF + ∠ABE = 180°

==> ∠BEF + 120° = 180° [co-interior ANGLE]

==> ∠BEF = (180° – 120°)

==> ∠BEF = 60°

Again, CD || EG and CE is the transversal.

∴ ∠CEG + ∠ECD = 180° [co-interior angle]

==> ∠CEG + 100° = 180°

==> ∠CEG = (180° – 100°)

==> ∠CEG = 80°

Now, FEG is a straight line.

∴ ∠BEF + ∠BEC + ∠CEG = 180°

==> 60° + x° + 80° = 180°

==> x + 140° = 180°

==> x = (180° – 140°)

==> x = 40°

Hence, the value of x is 40°

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