1.

In the given figure, AB and PQ intersect at M. If A and B are centres of circles then .....(A) PM = MQ(B) PQ ⊥ AB(C) Both (A) and (B)(D) PQ = AB

Answer»

The correct option is: (C) Both (A) and (B)

Explanation:

In the given figure, PQ is the common chord of the two circles.

=> AB bisects the common chord PQ at M.

 .'. PM = MQ

Moreover, PQ is perpendicular to AB.

.'. Option (C) is correct.



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