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In the given figure, AB and PQ intersect at M. If A and B are centres of circles then .....(A) PM = MQ(B) PQ ⊥ AB(C) Both (A) and (B)(D) PQ = AB |
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Answer» The correct option is: (C) Both (A) and (B) Explanation: In the given figure, PQ is the common chord of the two circles. => AB bisects the common chord PQ at M. .'. PM = MQ Moreover, PQ is perpendicular to AB. .'. Option (C) is correct. |
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