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In the given figure, AABC is a right-angled trianglein which Z A is 90°. Semicircles are drawn on ABAC and BC as diameters. Find the area of the shadedregion.7 |
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Answer» BC²=AC²+AB² =8²+6² =64+36 =100 BC=10cm Area of biggest semicircle= 1/2 * 3.14 * r² =0.5*3.14*5*5 =0.5*78.5 =39.25 cm² Area of 2nd Largest Semicircle = 0.5*3.14*r² =0.5*3.14*3² =0.5*3.14*9 =14.13 cm² Area of smallest Semicircle = 0.5*3.14*r² =0.5*3.14*4² =0.5*3.14*16 =25.12cm² Area of Triangle = 1/2 *b*h = 0.5*6*8 =24 cm² Area of shaded region = (24+25.12+14.13) - 39.25 = 63.25-39.25 =24 cm² |
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