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. In the given fig, AD is bisector of angleA of AABC.Show that AB> BD. |
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Answer» If AD is the bisector of ∠A of triangle ABC, show that AB>DB.Given AD is the bisector of ∠A of triangle ABCHence ∠DAB=∠DAC∠BDA is the exterior angle of the ∆DACHence ∠BDA> ∠DACor ∠BDA > ∠DAB Since ∠DAC=∠DAB→ AB > BD In a triangle sides opposite to greater angle is greater. |
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