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In the given fig AB diameter of a circle AC 6 cm and BC 8 cm find the area of the shaded portion |
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Answer» Answer: AB is the diameter =d of a CIRCLE. ΔABC has the diameter AB as base & the point C is on the circumference. AC=6 cm and BC=8 cm. To find out: AREA of shaded portion in the given circle. Solution: ∠ACB=90 o since ΔABC has been inscribed in a semicircle. ∴ΔABC is a right one with AB as hypotenuse ...(i) So, applying Pythagoras theorem, we have AB= (AC) 2 +(BC) 2
= (6) 2 +(8) 2
cm=10 cm=d. ∴ The RADIUS of the given circle = 2 d
= 2 10
cm=5 cm. i.e The Area of circle =πr 2 =3.14×5 2 cm 2 =78.5cm 2 . Again, Area of ΔABC= 2 1
×AC×BC (by i) = 2 1
×6×8cm 2 =24cm 2 . Now, Area of shaded region = Area of circle − area of ΔABC =(78.5−24)cm 2 =54.5cm 2 . |
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